A metal rod having linear expansion coefficient 2 ×10−5°C−1 has a length of 1 m at 20∘C. The temperature at which it is shortened by 1 mm is
From, I2 = I1 [ 1 + α(t2−t1)] t2 = t1+I2−I1I1α = 20 + −10−51.0×2×10−5 = -300C