A metal X forms a water soluble salt $XN{O}_3$. When an aqueous solution of $XN{O}_3$ is added to common salt solution, then a white precipitate fo compound Y is formed along with sodium nitrate solution. Metal X is said to be the best conductor of electricity and it does not evolve hydrogen when put in dilute hydrohloric acid.

(a) What is metal X ?

(b) What is salt $XN{O}_3$ ?

(c) Name the compound Y.

(d) Write the chemical equation of the reaction which takes place on reacting $XN{O}_3$ solution an common salt solution giving the physical states of all the reactants and products.

(e) What type of chemical reaction is illustrated by the above equation ?

Q. A metal X forms a water soluble salt XNO₃. When an aqueous solution of XNO₃ is added to common salt solution, then a white precipitate of compound Y is formed alongwith sodium nitrate solution. Metal X is said to be the best conductor of electricity and it does not evolve hydrogen when put in dilute hydrohloric acid.
(a) What is metal X?
(b) What is salt XNO₃?
(c) Name the compound Y.
(d) Write the chemical equation of the reaction which takes place on reacting XNO₃ solution and common salt solution giving the physical states of all the reactants and products.
(e) What type of chemical reaction is illustrated by the above equation?

Q. A red-brown metal X forms a salt XSO₄. When hydrogen sulphide gas is passed through an aqueous solution of XSO₄, then a black precipitate of XS is formed alongwith sulphuric acid solution.
(a) What could the salt XSO₄ be?
(b) What is the colour of salt XSO₄?
(c) Name the black precipitate XS.
(d) By using the formula of the salt obtained in (a) above, write an equation of the reaction which takes place when hydrogen sulphide gas is passed through its aqueous solution.
(e) What type of chemical reaction takes place in this case?

Q. A strip of metal X is dipped in a blue coloured salt solution YSO₄. After some time, a layer of metal Y from the salt solution is formed on the surface of metal strip X. Metal X is used in galvanisation whereas metal Y is used in making electric wires. Metal X and metal Y together form an alloy Z.
(a) What could metal X be?
(b) What could metal Y be?
(c) Name the metal salt YSO₄.
(d) What type of chemical reaction takes place when metal X reacts with salt solution YSO₄? Write the equation of the chemical reaction involved.
(e) Name the alloy Z.

Q.

A red-brown metal X forms a salt $XS{O}_4$. When hydrogen sulphide gas is passed through an aqueous solution of $XS{O}_4$, then a black precipitate of XS is formed alongwith sulphuric acid solution.

(a) What could the salt $XS{O}_4$ be ?

(b) What is the colous of salt $XS{O}_4$ ?

(c) Name the black precipitate XS.

(d) By using the formula of the salt obtained in (a) above, write an equation of the reaction which takes place when hydrogen sulphide gas is passed through its aqueous solution.

(e) What type of chemical reacion takes place in this case ?

Q.

Two metals X and Y form the salts $XS{O}_4$ and $Y_{2}S{O}_4$, respectively. The solution of salt $XS{O}_4$ is blue in colour whereas that of $Y_{2}S{O}_4$ is colourless. When barium chloride solution is added to $XS{O}_4$ solution, then a white precipitate Z is formed along with a salt which turns the solution green. And when barium chloride solution is added to $Y_{2}S{O}_4$ solution, then the same white precipitate Z is formed along with colourless common salt solution.

(a) What could the metal X and Y be ?

(b) Write the name and formula of salt $XS{O}_4$.

(c) Write the name and formula of salt $Y_{2}S{O}_4$.

(d) What is the name and formla of white precipitate Z ?

(e) Write the name and formula of the salt which turns the solution green in the first case.