A metallic rod of mass per unit length $0.5kg{m}^{-1}$ is lying horizontally on a smooth inclined plane which makes an angle of ${30}^o$ with the horizontal. The rod is not allowed to slide down by a passing a current through it when a magnetic field of induction $0.25T$ is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is

Q. On a smooth plane inclined at ${30}^0$ with the horizontal, a thin current-carrying metallic rod is placed parallel to the horizontal ground. The plane is located in a uniform magnetic field of 0.15 T in the vertical direction. For what value of current can the rod remain stationary? The mass per unit length of the rod is 0.03 kg $m^{-1}$.

Q. A horizontal rod of mass 0.01 kg and length 10 cm is placed on a frictionless plane inclined at an angle ${60}^o$ with the horizontal and with the length of rod parallel to the edge of the inclined plane. A uniform magnetic field is applied 'Vertically downwards. If the current through the rod is 1.73 A, then the value of magnetic field induction B for which the rod remains stationary on the inclined plane is

Q. A horizontal rod of mass $10g$ and length $10$ $cm$ is placed on a smooth plate inclined at an angle of ${60}^0$ with the horizontal and the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field of induction $B$ is applied vertically downwards. If the current through the rod is $1.73$ ampere, then the value of $B$ for which the rod remains stationary on the inclined plane is :
(Given $g=10m/s^2$)