A microscope is having objective of focal length $1\text{cm}$ and eye-piece of focal length $6\text{cm}$. If tube length is $30\text{cm}$ and image is formed at the least distance of distinct vision, what is the magnification produced by the microscope ? Take $D=25\text{cm}$.

Q. A compound microscope has a magnification of $30$. The focal length of the eye-piece is $5$ cm. If the final image is formed at the least distance of distinct vision $25cm$, the magnification produced by the objective is

Q. A compound microscope has a magnifying power $48$. The focal length of its eye-piece is $5cm$. If final image is formed at least distance of distinct vision $\left(25cm\right)$ then magnification of objective lens is

Q. In compound microscope the magnification is $95$, and the distance of object from objective lens $\frac{1}{3.8}\text{cm}$ and focal length of objective is $\frac{1}{4}\text{cm}.$ What is the magnification of eye piece when final image is formed at least distance of distinct vision ?

Q. A compound microscope having magnifying power 35 with its eye-piece of focal length 10 cm. Assume that the final image is at least distance of distinct vision then the magnification produced by the objective is

Q. A compound microscope has an objective lens of $1.0cm$ focal length and an eye-piece of $2.5cm$ of focal length. When the object is placed at $1.1cm$ from the objective, the final image is at the least distance of direct vision. Thus, the magnification produced is