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Byju's Answer
Standard XII
Chemistry
Derivation of Kp and Kc
A mixture of ...
Question
A mixture of
3
moles of
S
O
2
,
4
moles of
N
O
2
and
4
moles of
N
O
is placed in a
2.0
L
vessel.
S
O
2
(
g
)
+
N
O
2
(
g
)
⇌
S
O
3
(
g
)
+
N
O
(
g
)
.
At equilibrium, the vessel is found to contain
1
mole of
S
O
2
. Calculate the value of
K
c
.
Open in App
Solution
Reaction:
S
O
2
(
g
)
+
N
O
2
(
g
)
⇌
S
O
3
(
g
)
+
N
O
(
g
)
Initial Moles
3
4
0
4
At equilibrium
3-2=1
4-2=2
2
4+2=6
So,
K
c
=
[
S
O
3
]
[
N
O
]
[
S
O
2
]
[
N
O
2
]
=
2
×
6
1
×
2
=
6
The correct answer is 6
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Similar questions
Q.
An equilibrium mixture
S
O
2
(
g
)
+
N
O
2
(
g
)
⇌
S
O
3
(
g
)
+
N
O
(
g
)
was found to contain
0.6
mole of
S
O
2
,
0.2
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,
0.8
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and
0.3
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in a liter. vessel. How many moles of
N
O
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N
O
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Q.
The equilibrium mixture,
S
O
3
(
g
)
+
N
O
(
g
)
⇌
S
O
2
(
g
)
+
N
O
2
(
g
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contains 0.6 mol of
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O
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, 0.4 mol of No, 0.8 mol of
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O
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and 0.1 mol of
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O
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per litre. If 1 mol of NO is introduced into the reaction vessel, then the number of moles of
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O
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,
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O
,
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O
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a
n
d
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O
2
of each gas in the new
equilibrium in moles per litre will be:
Q.
Consider the reaction, whose
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c
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33
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g
)
+
N
O
2
(
g
)
⇌
S
O
3
(
g
)
+
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(
g
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If
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and
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at equilibrium?
Q.
A mixture of
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moles of
C
O
2
was allowed to react in a
1.0
L
container. The equilibrium mixture contains
0.124
mole of
C
O
2
. Calculate
K
c
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N
O
(
g
)
+
C
O
(
2
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g
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⇌
N
O
2
(
g
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+
C
O
(
g
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.
Q.
The equilirbium constant
K
c
for the reaction
S
O
2
(
g
)
+
N
O
2
(
g
)
⇌
S
O
3
(
g
)
+
N
O
(
g
)
is
16
. If
1
mole of each of all the four gases is taken in
1
d
m
3
vessel, the equilibrium concentration of
N
O
would be:
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