A non-conducting square sheet of side 10 m is charged with a uniform surface charge density, $σ = - 60 \frac{μ C}{m^{2}}$ . Find the magnitude and orientation of electric field vector due to the sheet at a point which is d = 0.02 mm away from the midpoint of the sheet.

3.39 x 10⁶ N/C, away from the sheet

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6.78 x 10⁶ N/C, towards the sheet

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3.39 x 10⁶ N/C, towards the sheet

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6.78 x 10⁶ N/C, away from the sheet

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Solution

The correct option is C
3.39 x 10⁶ N/C, towards the sheet

For the point 0.02 mm away, the sheet may be treated as an infinite large sheet.

Do you concur?

So, $| \to E | = \frac{σ}{2_{ε} 0} = \frac{1}{2} \frac{60 \times 10^{- 6}}{8.85 \times 10^{- 12}} \frac{N}{c}$

$= 3.39 \times 10^{6} \frac{N}{c}$ [approx]

Since the charge on the sheet is negative, field direction will be towards the sheet.

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A non-conducting square sheet of side 10 m is charged with a uniform surface charge density,σ=−60μCm2 . Find the magnitude and orientation of electric field vector due to the sheet at a point which is d = 0.02 mm away from the midpoint of the sheet.

A non-conducting square sheet of side 10 m is charged with a uniform surface charge density, $σ = - 60 \frac{μ C}{m^{2}}$ . Find the magnitude and orientation of electric field vector due to the sheet at a point which is d = 0.02 mm away from the midpoint of the sheet.