A nucleus with atomic number Z and neutron number N undergoes two decay processes. The result is a nucleus with atomic number Z-3 and neutron number N-1. Which decay processes took place?

Q. When a nucleus with atomic number $Z$ and mass number $A$ undergoes a radioactive decay process,

$\left(1\right)$ Both $Z$ and $A$ will decrease, if the process is $\alpha$ decay.
$\left(2\right)$ $Z$ will decrease, but $A$ will not change, if the process is ${\beta }^{+}$ decay.
$\left(3\right)$ $Z$ will increase, but $A$ will not change, if the process is ${\beta }^{-}$ decay.
$\left(4\right)$ $Z$ and $A$ will remain unchanged, if the process is $\gamma$ decay.

Q. When a nucleus, having atomic number $Z$ and mass number $A$, undergoes a radioactive decay process,

1) Both $Z$ and $A$ will decrease, if the process is $\alpha$ decay.
2.) $Z$ will decrease but $A$ will not change, if the process is ${\beta }^{+}$ decay.
3.) $Z$ will increase but $A$ will not change, if the process is ${\beta }^{-}$ decay
4.) $Z$ and $A$ will remain unchanged, if the process is $\gamma$ decay

Q. STATEMENT - 1 : ${}_Z{X}^A$ undergoes 2 $\alpha$ decays, 2$\beta$ decays (negative $\beta$) and 2 decays. As a result the daughter product is
${}_{Z-2}{Y}^{A-8}.$
STATEMENT -2 : In $\alpha$ decay the mass number decreases by 4 unit and atomic number decreases by 2 unit. In $\beta$ decay (negative $\beta$) the mass number remains unchanged and atomic number increases by 1 unit. In $\gamma$ decay, mass number and atomic number remains unchanged.

Q. Assertion :${{}_{z}X}^A$ undergoes $2$ $\alpha$- decays, $2$ $\beta$- decays (negative $\beta$) and $2$ $\gamma$-decays. As a result , the daughter product is ${{}_{z-2}Y}^{A-8}$ Reason: In $\alpha$- decay, the mass number decreases by $4$ unit and atomic number decreases by $2$ unit. In $\beta$- decay (negative $\beta$), the mass number remains unchanged and atomic number increaess by $1$ unit. In $\gamma$-decay, mass number and atomic number remain unchanged

Q. A plot of the number of neutrons (N) against the number of protons (P) of stable nuclei exhibits upward deviation from linearity for atomic number, Z > 20. For an unstable nucleus having $\frac{N}{P}$ ratio less than 1, the possible mode(s) of decay is(are)