A number consists of three digits whose sum is 10. The middle digit is equal to sum of the other two and when the number is increased by 99, the first digit and the third digit get interchanged. The digit in the hundreds place is

The correct option is D 2
Let the number be abc.
abc + 99 = cba
100a + 10b + c +99 = 100c + 10b + a
99(c - a) = 99
c - a = 1
Also, a + c = b
& a + b + c = 10
so, 2b = 10
b = 5
Now, a + c = 5
c - a = 1
so, 2c = 6
c = 3 & a = 2
so, the required number is 253 and the digit 2.