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Question

A particle A is moving with a speed of 10 m/s towards right and another particle B is moving at speed of 12 m/s towards left. Find their velocity of approach.

A
2 m/s
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B
10 m/s
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C
12 m/s
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D
22 m/s
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Solution

The correct option is D 22 m/s
Velocity of particle A, VA=+10
Velocity of particle B, VB=12
Velocity of approach, VAB=VAVB
VAB=10(12)=22 m/s
Velocity of approach = 22 m/s

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