A particle A is moving with a speed of 10m/s towards right and another particle B is moving at speed of 12m/s towards left. Find their velocity of approach.
A
−2m/s
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B
10m/s
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C
12m/s
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D
22m/s
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Solution
The correct option is D22m/s Velocity of particle A, VA=+10
Velocity of particle B, VB=−12
Velocity of approach, VAB=VA−VB ⇒VAB=10−(−12)=22m/s
Velocity of approach = 22m/s