A particle A is moving with a speed of 20m/s towards right and another particle B is moving at a speed of 5m/s towards right. Find their velocity of approach.
A
5m/s
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B
15m/s
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C
20m/s
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D
25m/s
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Solution
The correct option is B15m/s Velocity of particle, VA=+20
Velocity of particle, VB=+5
Velocity of approach, VAB=VA−VB VAB=20−(+5)=15m/s
Hence the approach velocity, Vapp=|VAB|=15m/s