A particle A of mass 107kg is moving in the positive x− direction. Its initial position is x=0 and initial velocity is 1m/s. The velocity at x=10m in m/s (use the graph given). Answer the nearest integer.
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Solution
From graph, P=0.2x+2=Fv=mav or mvdvdxv=0.2x+2 or mv2dv=(0.2x+2)dx Now integrate both sides, v∫1mv2dv=10∫1(0.2x+2)dx⇒v=4m/s