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Question

A particle A of mass 107 kg is moving in the positive x direction. Its initial position is x=0 and initial velocity is 1 m/s. The velocity at x=10 m in m/s (use the graph given). Answer the nearest integer.

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Solution

From graph,
P=0.2x+2=Fv=mav
or mvdvdxv=0.2x+2
or mv2dv=(0.2x+2)dx
Now integrate both sides,
v1mv2dv=101(0.2x+2)dxv=4 m/s

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