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Question

A particle is ejected from the tube at A with a velocity v at an angle θ with the y-axis as shown in figure. A strong horizontal wind gives the particle a constant horizontal acceleration a in the x-direction. If the particle strikes the ground at a point directly under its released position and the downward y acceleration is taken as g, find the height h of the particle.
828375_d95ab6075cd64402808016cfbb2757f8.png

A
h=2v2sinθcosθa
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B
h=2v2sinθcosθg
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C
h=2v2gsinθ(cosθ+agsinθ)
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D
h=2v2asinθ(cosθ+gasinθ)
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Solution

The correct option is D h=2v2asinθ(cosθ+gasinθ)
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