A particle is executing simple harmonic motion with an amplitude $A$ and time period $T$. The displacement of the particles after $2T$ period from its initial position is

Q. The displacement of a particle in simple harmonic motion having Amplitude 'A' after one time period is :

Q. A particle executes a simple harmonic motion of time period $T$. Find the time taken by the particle to go directly from its mean position to half the amplitude.

Q. A particle performing simple harmonic motion undergoes initial displacement of $A/2$ (where $A$ is the amplitude of simple harmonic motion) in $1s$ . At $t=0$ , the particle may at the extreme position (or) mean position . The time period of the simple harmonic motion can be

Q. The displacement of a particle executing simple harmonic motion is given by equation y=0.3 sin 20$\pi$ (t+0.05) where time t is in second and displacement y is in metre. calculate the values of amplitude, time period initial phase and initial displacement of the particle .

Q. A particle is executing simple harmonic motion with a period of T seconds and amplitude A metre, The shortest time it takes to reach a point $\frac{A}{\sqrt{2}}m$ from its mean position in seconds is