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Centripetal Acceleration

A particle is...

Question

A particle is moving along a circular path of radius $5 m$ with a uniform speed $5 m s^{- 1}$ . What is the magnitude of average acceleration during the interval in which particle completes half revolution?

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Solution

$T i m e = \frac{2 π \times 5}{5 \times 2} = \frac{2 π}{2} s e c = π s e c$
$A v e r a g e A c c e l e r a t i o n = \frac{Δ V e l o c i t y}{T i m e} = \frac{5 - (- 5)}{π} = \frac{10}{π} m / s^{2}$

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