A particle is projected down on inclined plane with a velocity of $21m/s$ at an angle of ${60}^o$ with the horizontal. Its range on the inclined plane, inclined at an angle of ${30}^o$ with the horizontal is

Q. A projectile is projected with speed $u$ at an angle of ${60}^o$ with horizontal from the foot of an inclined plane. If the projectile hits the inclined plane horizontally, the range on inclined plane will be

Q. A particle is projected with some velocity $u$ making an angle ${60}^0$ with horizontal up an inclined plane. The plane makes an angle ${30}^0$ with horizontal. The particle's range on the inclined plane with it's time of flight $T$, is :

Q. An inclined plane makes an angle ${\theta }_0={30}^o$ with the horizontal. A particle is projected from this plane with a speed of $5m{s}^{-1}$ at an angle of elevation $\beta ={30}^o$ with the horizontal as shown in Fig.
a. Find the range of the particle on the plane when it strikes the plane.
b. find the range of the particle for $\beta =120$

Q. An inclined plane is making an angle $\beta$ with horizontal. A projectile is projected from the bottom of the plane with a speed $u$ at an angle $\alpha$ with horizontal then its range $R$ when it strikes the inclined plane is :