wiz-icon
MyQuestionIcon
MyQuestionIcon
58
You visited us 58 times! Enjoying our articles? Unlock Full Access!
Question

A particle is projected from a point A with velocity u=6 at an angle of 45o with horizontal as shown in figure. It strikes the plane BC normally. Find the velocity (in m/s) of the particle just before the collision.


Open in App
Solution

Equating horizontal velocities,

6cos 45o=v.32
2×312=v.32
v=2 m/s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Time, Average Speed and Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon