A particle is projected from a top of a tower of ht 20m with a speed 20m/s at an unknown angle. its speed just before hitting the ground is (g =10m/s2) 1. 20m/s 2. 20 root2 m/s

Q. A particle is thrown horizontally with $20m/s$ from the top of a tower of height $20m(g=10m/s^2)$. Angle with horizontal at which it will hit the ground is:-

Q. A particle is given horizontal projection from the top of a tower with the speed 20 m/s. What will be the angle of its velocity with horizontal after 2s (g = 10m/$s^2$)

Q. A body is projected from the top of a tower of height $32\text{m}$ with a velocity of $20\text{m/s}$ at an angle of ${37}^{\circ }$ above the horizontal. Find the horizontal distance travelled before it hits the ground.
(Take $g=10m/s^2$)

Q. Two particles $A$ and $B$ are projected simultaneously from the top of two towers of height $10\text{m}$ and $20\text{m}$ respectively. Particle $A$ is projected upwards at an angle of ${45}^{\circ }$ with horizontal at a speed of $10\sqrt{2}\text{m/s}$ and particle $B$ is projected horizontally at a speed of $10\text{m/s}$ towards $A$. What is the distance between towers if particles collide in the air ?Take $g=10{\text{m/s}}^2$.

Q. A body is projected from the top of a tower of height $32\text{m}$ with a velocity of $20\text{m/s}$ at an angle of ${37}^{\circ }$ above the horizontal. Find the angle below the horizontal with which it hits the ground.
(Take $g=10m/s^2$)