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Question


A particle is projected from ground as shown. It is at point A at time t1, at point B at time t2, at point C at time t3 & at time t4 it is at D then

A
VBVA=VDVC
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B
VAt1=VBt2=VCt3=VDt4
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C
VBVAt2t1=VDVCt4t3
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D
VA+VB2=VC+VD2
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Solution

The correct option is C VBVAt2t1=VDVCt4t3
During motion a is constant hence ΔVΔt is same for all intervals.

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