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Question

A particle is projected from point A , that is at a distance 4R from the centre of the Earth, with speed V0 as shown. If the particle passes grazing the earth's surface, then it is found that V0=4000×N. Find the value of N.
[Take GMR=6.4×107m2s2]


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Solution

Applying conservation of angular momentum with respect to the centre of earth,
4R×mv0sin 300=mvR
v=2v0
applying energy conservation
12m(2v0)2GMmR=GMm4R+12mv20
v0=GM2R=64×1062=42×1000ms
On comparing
N=2

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