A particle is projected from point o with velocity v1 at angle 30 degree with the horizontal and another paeticle is projected from point p which os vertically below the highest point with velocity v2 in the vertical upward direction For two particles to collide ythe raatio v1/v2will be

Q.

A particle P is projected with velocity $u_1$ at an angle of ${30}^{\circ }$ with the horizontal. Another particle Q is thrown vertically upwards with velocity $u_2$ from a point vertically below the highest point of path of P. The necessary condition for the two particles to collide at the highest point is

Q. A body is projected with velocity $v_1$ from the point $A$ as shown in Fig. At the same time, another body is thrown vertically upward from $B$ with velocity $v_2$. Point B lies vertically below the highest point. For both the bodies to collide, $\frac{v_2}{v_1}$ should be

Q. A body is projected with velocity $v_1$ from the point $A$, another body at the same time is projected vertically upwards from $B$ with velocity $v_2$ as shown in adjoining figure. If the point $B$ lies vertically below the highest point $C$, then for both bodies to collide the ratio $\frac{v_2}{v_1}$ should be

Q. A body is projected at ${30}^{\circ }$ with velocity $v_1$ from point $A$ on the ground. At the same time another body is projected vertically upwards from $B$ with velocity $v_2$ from the ground. The point $B$ lies vertically below the highest point of the trajectory of ball $A$. For both the bodies to collide, what should be the ratio of $v_1/v_2$ ?

Q. A body is projected at ${30}^{\circ }$ with velocity $v_1$ from point $A$ on the ground. At the same time, another body is projected vertically upwards from $B$ with velocity $v_2$ from the ground. The point $B$ lies vertically below the highest point of the trajectory of ball $A$. For both the bodies to collide, what should be the ratio of $\frac{v_1}{v_2}$ ?