A particle is projected vertically up with velocity v=4gR/3 from earth surface. The velocity of particle at height equal to half of maximum height reach by it

Q. A particle is thrown vertically upwards from the surface of earth and it reaches to a maximum height equal to the radius of earth. The ratio of the velocity of projection to the escape velocity on the surface of earth is

Q. A particle is projected vertically upwards from the surface of the earth (radius $R)$ with a speed equal to one-fourth of escape velocity. The maximum height attained by it from the surface of the earth is

Q. A particle of mass $m$ is projected with a velocity $v=k{v}_e(k<1)$ from the surface of the earth. $(v_e=$ escape velocity$)$. The maximum height above the surface reached by the particle is -

$R$ is the radius of earth.

Q. A body is projected vertically from the surface of the earth of radius $R$ with a velocity equal to half of the escape velocity. The maximum height reached by the body is:

Q. A particle is projected vertically upwards the surface of the earth (radius $R_e$) with a speed equal to one fourth of escape velocity. What is the maximum height attained by it ?