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Question

A particle is projected with speed u at angle θ with horizontal from ground. If it is at same height from ground at time t1 and t2, then its average velocity in time interval t1 to t2 is

A
Zero
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B
usinθ
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C
ucosθ
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D
12[ucosθ]
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Solution

The correct option is C ucosθ
Average velocity =totaldisplacementinxtotaltime
=ucosθ(t2t1)(t2t1)
=ucosθ

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