A particle of mass m having a charge q enters into a circular region of radius R with velocity v directed towards the centre. The strength of magnetic field is B. Find the deviation in the path of the particle.
A
π−tan−1(mvqBR2)
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B
π−2tan−1(mvqBR)
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C
π+tan−1(mvqBR2)
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D
π+2tan−1(mvqBR)
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Solution
The correct option is Bπ−2tan−1(mvqBR)
In ΔOBC, tanα=rR ⇒α=tan−1(rR) =tan−1(mvqBR)
Now, deviation, δ=π−2α =π−2tan−1(mvqBR)