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Question

A particle of mass m having a charge q enters into a circular region of radius R with velocity v directed towards the centre. The strength of magnetic field is B. Find the deviation in the path of the particle.

A
πtan1(mvqBR2)
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B
π2 tan1(mvqBR)
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C
π+tan1(mvqBR2)
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D
π+2 tan1(mvqBR)
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Solution

The correct option is B π2 tan1(mvqBR)

In ΔOBC, tan α=rR
α=tan1(rR)
=tan1(mvqBR)
Now, deviation, δ=π2α
=π2 tan1(mvqBR)

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