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Oblique Collision

A particle of...

Question

A particle of mass m moving with a speed v hits elastically another stationary particle of mass 2 m on a smooth horizontal circular tube of radius r. The time in which the next collision will take place is equal to

A

\frac{2 π r}{v}

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B

\frac{4 π r}{v}

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C

\frac{3 π r}{2 v}

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D

\frac{π r}{v}

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Solution

The correct option is A $\frac{2 π r}{v}$
Relative velocity of separation
= relative velocity of approach
= v (as e=1)
$∴$ Time of next collision $= \frac{2 π r}{v}$

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