A person's eye is at a height of 1.5m. He stands in front of a 0.3m long plane mirror whose lower end is 0.8m above the ground. The length of the image he sees himself is?

Given Data:

Height of eye, $h=1.5m$

Length of mirror, $l=0.3m$

Height of mirror, $h^{\prime }=0.8m$

Step 1: Length of image:

Here, eyes of man different with top and bottom edge of mirror.

Hence, image will be twice the height of mirror irrespective of other measurements, $=2\times 0.3m=0.6m$

Therefore, the man sees $\text{0.6m}$ of himself in mirror.