A plane mirror and an object approach each other with speeds of 5m/s and 10 m/s respectively. The speed of the image will be __.

Open in App

Solution

Total speed of the image = Speed of the object + 2 $\times$ Speed of the mirror = 10 + 2 $\times$ 5 = 20 $\frac{m}{s e c}$

Suggest Corrections

Similar questions

A plane mirror and an object approach each other with speeds of 5m/s and 10 m/s respectively. The speed of the image will be 20 $\frac{m}{s e c}$ .

A plane mirror and an object approach each other with speeds of 5m/s and 10 m/s respectively. The speed of the image will be

A plane mirror and an object approach each other with speeds of $5 m s^{- 1}$ and $10 m s^{- 1}$ respectively. What will be the speed of the image w.r.t. the stationary observer?

Q. Rohan and a plane mirror are approaching each other with speeds of 5 m/s and 10 m/s, respectively. The speed of the image will be:

A plane mirror and an object approach each other with speeds of $5 m s^{- 1}$ and $10 m s^{- 1}$ respectively. What will be the speed of the image w.r.t. the stationary observer?

Join BYJU'S Learning Program

A plane mirror and an object approach each other with speeds of 5m/s and 10 m/s respectively. The speed of the image will be __.

Total speed of the image = Speed of the object + 2 × Speed of the mirror = 10 + 2 × 5 = 20 msec

Total speed of the image = Speed of the object + 2 $\times$ Speed of the mirror = 10 + 2 $\times$ 5 = 20 $\frac{m}{s e c}$