wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A planet moves around sun in nearly circular orbit period of revolution 't', radius of orbit r mass of sun m.

Time period if direcyly proportional to mass of sun, distance between planet and sun and universal gravitational constant.

Prove T​​​​​​2 is directly proportional to r​​​​​​3

Open in App
Solution

YOUR ANSWER GOES IN THE WAY OF LAW STATED BY KEPLER.

3rd LAW OF KEPLER:

T² ∝R³

PROOF :

It is known as Law of periods..

Let us consider a planet P of mass m moving with a velocity v around the sun of mass M in a circular orbit of radius r.

The gravitational force of attraction of the sun on the planet is,

F=GMm/r².

The centripetal force is,F = mv²/r.

equating the two forces,

mv²/r=GMm/r².

v²=GM/r -----›(i)

If T be the period of revolution of the planet around the sun, then

v=2πr/T-------›(ii)

Substituting (ii) in (i)

4π²r²/T²=GM/r

r³/T²=GM/4π²

GM is a constant for any planet.

•°• T²∝R³.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Variation in g
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon