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Question
A point object is moving with velocity v0=10^i m/s along x-axis as shown in figure. Relative velocity of its image in mirror M1 with respect to mirror image velocity in M2 is :
(Take sin 37∘=0.6)
A point object is moving with velocity v0=10^i m/s along x-axis as shown in figure. Relative velocity of its image in mirror M1 with respect to mirror image velocity in M2 is :
(Take sin 37∘=0.6)
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Solution
The correct option is C 12 m/s
→v1i=−10^i
→v2i=(6 cos 53∘−8 cos 37∘)^i+(6 sin 53∘+8 sin 37∘)^j
=(3.6−6.4)^i+(4.8+4.8)^j
=−2.8^i+9.6^j
→v12=−7.2^i−9.6^j
v12=√7.22+9.62
=2.4√32+42
=12 m/s
12 m/s
→v1i=−10^i
→v2i=(6 cos 53∘−8 cos 37∘)^i+(6 sin 53∘+8 sin 37∘)^j
=(3.6−6.4)^i+(4.8+4.8)^j
=−2.8^i+9.6^j
→v12=−7.2^i−9.6^j
v12=√7.22+9.62
=2.4√32+42
=12 m/s
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