A pole has to be erected at a point on the boundary of a circular park of diameter 13 meters in such a way that the difference of its distance from two diametrically opposite fixed gates A and B on the boundary is 7 meters. Is it the possible to do so? If yes, at what distances from the two gates should the pole be erected?

Q. A straight pole has to be erected at a point on the outer boundary of a circular park having diameter 13 meters in such a way as that the differences of its distances from two diametrically opposite gates C and D fixed on the boundary in 7 meters. Is it possible to do so? If yes what is the sum of distances from the two gates should the straight pole be erected?

Q. A pole has to be erected at a point on the boundary of a circular park of diameter 13 metres in such a way that the difference of its distances from two diametrically opposite fixed gates A and B on the boundary is 7 metres. Is it the possible to do so? If yes, at what distances from the two gates should the pole be erected?

Q. Poles are to be fixed along the boundary of a rectangular field in such a way that distance between any two adjacent poles is 2 m.The perimeter of the field is 70m and length and the breadth of the field are in the ratio 4:3 resp. How many poles will be required?

Q. AB is a vertical pole fixed to the ground, with A being the point where the base of the pole touches the ground. Due to a cyclone, the pole has been broken at C which is at a height of 24 meters from the ground. The broken part is partially attached to the pole at C. If the end of the broken part B touches the ground at D which is at a distance of 7 meters from A, then the original height of the pole is: