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Projectile Time, Height and Range

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Question

A projectile is fired horizontally with a velocity of $98 m / s$ from the top of a hill $490 m$ high. Find the time taken by the projectile to reach the ground.

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Solution

Given : $u_{x} = 98 m / s$ $a_{y} = g = 9.8 m / s^{2}$

Height of the hill $S_{y} = h = 490$ m

$∴$ Time of flight $T = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 (490)}{9.8}} = 10$ s

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