A projectile is thrown into space so as to have maximum horizontal range R. Taking the point of projection as origin, the co-ordinates of the point where the speed of the particle is minimum are

The correct option is C

For maximum horizontal Range $\theta ={45}^{\circ }$

From R = 4H $cot\theta$ = 4H [As $\theta ={45}^{\circ }$, for maximum range.]

Speed of the particle will be minimum at the highest point of parabola. So the co-ordinate of the highest point will be $(\frac{R}{2},\frac{R}{4})$