A projectile thrown with a speed v at an angle $\theta$ has a range R on the surface of earth. For same v and $\theta$, its range on the surface of moon will be

Q.

A projectile thrown with a speed v at an angle $\theta$ has a range R on the surface of earth. For same v and $\theta$, its range on the surface of moon will be

Q. A projectile thrown with a speed v at an angle $\theta$ has a range R on the surface of earth.For the same v and $\theta$, its range on the surface of moon will be $[g_{moon}=\frac{g_{earth}}{6}]$

Q. A projectile thrown with an initial speed $u$ and the angle of projection ${15}^o$ to the horizontal has a range $R$. If the same projectile is thrown at an angle of ${45}^o$ to the horizontal with speed $2u$, what will be its range?

Q.

A projectile thrown with an initial speed u and angle of projection ${15}^{\circ }$ to the horizontal has a range R. If the same projectile is thrown at an angle of ${45}^{\circ }$ to the horizontal with speed 2u, its range will be

Q. The range of a projectile at an angle $\theta$ is equal to half of the maximum range if thrown at the same speed. The angle of projection $\theta$ is given by :