A ray incident at an angle of incidence 60∘ enters a glass sphere of refractive index μ=√3. This ray is reflected and refracted at the farther surface of the sphere. The angle between reflected and refracted rays at this surface is
A
90∘
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B
60∘
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C
70∘
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D
40∘
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Solution
The correct option is A90∘
μ=sinisinr ∴sinr=siniμ =sin60∘√3=12 ∴r=30∘ PC = QC ∴∠CPQ=∠PQC=∠r=30∘ Angle between reflected ray QR and refracted ray QS at the other face is 180∘–r–60∘ or 90∘(asr=30∘).