A ray of light strikes a mirror at an angle of - 60 - o- -160-to the normal- The mirror is then rotated -160- 18 - o- -160-anticlockwise- What is the angle that the initial -160-reflected ray and final reflected ray will have- -160- 18 - o- 20 - o- 36 - o- 54 - o-

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Question

A ray of light strikes a mirror at an angle of $60^{o}$ to the normal. The mirror is then rotated $18^{o}$ anticlockwise, What is the angle that the initial reflected ray and final reflected ray will have?

18^{o}

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20^{o}

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36^{o}

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54^{o}

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Solution

The correct option is C $36^{o}$
When the mirror rotates , the angle of reflection rotates too. so,the angle of reflection rotates by $2 \times 18 = 36^{0}$
since,the angle of reflection $=$ angle of incidence.
so,the deflection will be same.

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A ray of light strikes a mirror at an angle of 60o to the normal. The mirror is then rotated 18o anticlockwise, What is the angle that the initial reflected ray and final reflected ray will have?

The correct option is C 36o When the mirror rotates , the angle of reflection rotates too. so,the angle of reflection rotates by 2×18=360since,the angle of reflection = angle of incidence.so,the deflection will be same.

A ray of light strikes a mirror at an angle of $60^{o}$ to the normal. The mirror is then rotated $18^{o}$ anticlockwise, What is the angle that the initial reflected ray and final reflected ray will have?

The correct option is C $36^{o}$
When the mirror rotates , the angle of reflection rotates too. so,the angle of reflection rotates by $2 \times 18 = 36^{0}$
since,the angle of reflection $=$ angle of incidence.
so,the deflection will be same.