A ray of light travelling in a medium of refractive index - - is incident at an angle - - on a composite transparent plate consisting of 50 plates of - R-I-1-01 - 1-02- 1-03 - - 1-50 - The ray emerges from the composite plate into a medium of refractive index - 1-6 - at angle -x- then-sin x- - 1-01-1-5 -50sin -sin x- 5-8 sin -sin x- -5-9- sin -sin x- 101-160 sin -

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Byju's Answer

Standard X

Physics

Minimum Deviation

A ray of ligh...

Question

A ray of light travelling in a medium of refractive index $μ$ is incident at an angle $θ$ on a composite transparent plate consisting of 50 plates of $R . I .1 .01 μ, 1.02 μ, 1.03 μ, . . . . . . 1.50 μ$ The ray emerges from the composite plate into a medium of refractive index $1.6 μ$ at angle 'x' then,

sin x=

{(\frac{1.01}{1.5})}^{50} s i n θ

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sin x=

\frac{5}{8} s i n θ

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sin x=

(\frac{5}{9}) s i n θ

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sin x=

\frac{101}{160} s i n θ

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Solution

The correct option is B sin x= $\frac{5}{8} s i n θ$
Refractive index and angle of incidence in initial medium is given by $μ$ and $θ$ respectively.
Similarly for the final medium, Refractive index and angle of emergence is given by $1.6 μ$ and $x$ respectively.
As, $\frac{μ}{1.6 μ} = \frac{s i n (x)}{s i n (θ)}$
So, $s i n (x) = \frac{5}{8} s i n (θ)$

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Similar questions

Q. A ray of light travelling in a medium of refractive index

μ

is incident at an angle

θ

on a composite transparent plate consisting of 50 plates of

R . I . 1.01 μ, 1.02 μ, 1.03 μ

, ........ ,

1.50 μ

. The ray emerges from the composite plate into a medium of refractive index

1.6 μ

at angle x . Then:

A ray of light, travelling in a medium of refractive index $μ$ , is incident at an angle i on a composite transparent plate consisting of three plates of refractive indices $μ_{1}, μ_{2} a n d μ_{3}$ . The ray emerges from the composite plate into a medium of refractive index $μ^{,}$ , at angle x, Then