A ray of light travels in the fashion as shown in the figure. After passing through water, the ray grazes along the water-air interface. The value of $μ_{g}$ in terms of $i$ is

\frac{1}{sin i}

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\frac{3}{sin i}

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\frac{2}{sin i}

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\frac{4}{sin i}

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Solution

The correct option is A $\frac{1}{sin i}$
For any pair of media,
$μ sin θ =$ constant

So, from figure,
$μ_{g} sin i = μ_{w} sin r = μ_{a} sin e$
$\Rightarrow μ_{g} sin i = μ_{a} sin e$
$\Rightarrow μ_{g} sin i = 1 \times sin 90^{\circ}$
$\Rightarrow μ_{g} = \frac{1}{sin i}$

Why this question?
Tips: Identify the number of interfaces at which light is undergoing refraction and apply Snell's law.

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