A room contains 35 kg of dry air and 0.5 kg of water vapor. The total pressure and temperature of air in the room are 100 kPa and ${25}^{\circ }C$ respectively. Given that the saturation pressure for water at ${25}^{\circ }C,$ is 3.17 kPa, the relative humidity of the air in the room is

Q. The pressure, dry bulb temperature and relative humidity of air in a room are 1 bar, ${30}^{\circ }C$ and 70%, respectively. If the saturated steam pressure at ${30}^{\circ }C$ is 4.25 kPa, the specific humidity of the room air in kg of water vapour/kg dry air is

Q. Moist air is filled inside a room with total pressure of 100 kPa, and at ${25}^{\circ }$C. If the moist air is saturated with mass of dry air as 50 kg, the mass of vapour in the room is (use saturation pressure of water at ${25}^{\circ }C$ as 3.17 kPa)

Q. A moist air sample has dry bulb temperature of ${30}^{\circ }C$ and specific humidity of 11.5 g water vapour per kg dry air. Assume molecular weight of air as 28.93. If the saturation vapour pressure of water at ${30}^{\circ }C$ is 4.24 kPa and the total pressure is 90 kPa, then the relative humidity (in %) of air sample is

Q.

The condition of air in a closed room is described as follows. Temperature = ${25}^0$ C, relative humidity = 60 %, pressure = 104 kPa. If all the water vapour is removed from the room without changing the temperature, what will be the new pressure ? The saturation vapour pressure at ${25}^0$ C = 3.2 kPa.

Q. The condition of air in a closed room is described as follows. Temperature = 25°C, relative humidity = 60%, pressure = 104 kPa. If all the water vapour is removed from the room without changing the temperature, what will be the new pressure? The saturation vapour pressure at 25°C − 3.2 kPa.