You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Laws of Definite Proportions, Multiple Proportions

A sample of c...

Question

A sample of calcium carbonate $(C a C O_{3})$ has the following percentage composition $C a = 40 %; C = 12 %; O = 48 %$
If the law of constant proportions is true, then the weight of calcium in $4 g$ of a sample of calcium carbonate from another source will be

0.016 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.16 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.6 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1.6 g$
$\Rightarrow 100 g$ of $C a C O_{3}$ produces $40 g$ of $C a$
$\Rightarrow 1 g$ of $C a C O_{3}$ will produce $\frac{40}{100} g$ of $C a$
$\Rightarrow$ Weight of $C a$ in $4 g$ of a sample of calcium carbonate from another source will be $= \frac{40}{100} \times 4 = 1.6 g$

Suggest Corrections

Similar questions

Q. A sample of calcium carbonate

(C a C O_{3})

has the following percentage composition:

C a = 40 %; C = 12 %; O = 48 %

.
If the law of constant proportions is true, then the weight of calcium in

4 g

of a sample of calcium carbonate from another source will be:

Q. A sample of

C a C O_{3}

has

C a = 40 %

C = 12 %

and

O = 48 %

. if the law of constant proportions is true, then the weight of Calcium in

4 g

of a sample of calcium carbonate from another source will be:

Q. The percentage composition in a sample of

C a C O_{3}

is given as:

C a = 40 %; C = 12 %; O = 48 %

. What will be the weight of

C a

4 g

of a sample of

C a C O_{3}

obtained from another source, if the law of constant proportions is true?

Q. A sample of

{C a C O}_{3}

has

C a = 40

C = 12

% and

O = 48

%. If the law of constant proportion is true then the weight of calcium in

5 g

of a sample of

{C a C O}_{3}

from another source will be:

Q. The percentage composition in a sample of

C a C O_{3}

is given as:

C a = 40 %; C = 12 %; O = 48 %

. What will be the weight of

C a

4 g

of a sample of

C a C O_{3}

obtained from another source, if the law of constant proportions is true?

Join BYJU'S Learning Program

Explore more

Laws of Definite Proportions, Multiple Proportions

Standard XII Chemistry

Join BYJU'S Learning Program

A sample of calcium carbonate (CaCO3) has the following percentage composition Ca=40%;C=12%;O=48% If the law of constant proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate from another source will be

The correct option is C 1.6 g⇒100 g of CaCO3 produces 40 g of Ca ⇒1 g of CaCO3 will produce 40100 g of Ca ⇒Weight of Ca in 4 g of a sample of calcium carbonate from another source will be =40100×4=1.6 g

A sample of calcium carbonate $(C a C O_{3})$ has the following percentage composition $C a = 40 %; C = 12 %; O = 48 %$
If the law of constant proportions is true, then the weight of calcium in $4 g$ of a sample of calcium carbonate from another source will be