A sample of vitamin C contains 2-48-1025 oxygen atoms- How many moles of oxygen atoms are present in the sample-

As we know:Given the number of oxygen atoms in the sample 2.48×10^25 atoms One mole of oxygen atoms = 6.022×10^23N_Aor 6.022×10^23N_A=1 mole So 2.48×10^25oxyg ...

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Standard IX

Chemistry

Mole Concept & Avogadro Number

A sample of v...

Question

A sample of vitamin C contains $2.48 \times 10^{25}$ oxygen atoms. How many moles of oxygen atoms are present in the sample?

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Solution

As we know:
Given the number of oxygen atoms in the sample - $2.48 \times 10^{25}$ atoms
One mole of oxygen atoms = $6.022 \times 10^{23} N_{A}$
or $6.022 \times 10^{23} N_{A}$ =1 mole
So $2.48 \times 10^{25}$ oxygen atom= $\frac{2.48 \times 10^{25}}{6.022 \times 10^{23}}$ = 41.18 mole
So, A sample of vitamin C contains 41.18 moles of oxygen atoms.

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A sample of vitamin C contains 2.48×1025 oxygen atoms. How many moles of oxygen atoms are present in the sample?

As we know:Given the number of oxygen atoms in the sample -2.48×1025 atoms One mole of oxygen atoms = 6.022×1023NAor 6.022×1023NA=1 mole So 2.48×1025oxygen atom=2.48×10256.022×1023= 41.18 moleSo, A sample of vitamin C contains 41.18 moles of oxygen atoms.

A sample of vitamin C contains $2.48 \times 10^{25}$ oxygen atoms. How many moles of oxygen atoms are present in the sample?