A school team won 6 games this year and 4 games last year. What is the percent increase ?

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Solution

Given that the school won 6 games this year against 4 won last year
Increase in number of wins = 6 – 4 = 2
Hence per cent increase = (2/4) × 100
= (1/2) × 100
= 50%
Thus the percentage increase in winning the games this year is 50%.

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A school team won 6 games this year and 4 games last year. What is the percent increase ?

Given that the school won 6 games this year against 4 won last year Increase in number of wins = 6 – 4 = 2 Hence per cent increase = (2/4) × 100 = (1/2) × 100 = 50% Thus the percentage increase in winning the games this year is 50%.

Given that the school won 6 games this year against 4 won last year
Increase in number of wins = 6 – 4 = 2
Hence per cent increase = (2/4) × 100
= (1/2) × 100
= 50%
Thus the percentage increase in winning the games this year is 50%.