A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of a radius 30 m. What horizontal force on the scooter is needed to make the turn possible?

Open in App

Solution

Given:
Mass = m = 150 kg
Speed = v = 36 km/hr = 10 m/s
Radius of turn = r = 30 m
Let the horizontal force needed to make the turn be F. We have:
$F = \frac{m v^{2}}{r} = \frac{150 \times (10)^{2}}{30} = \frac{150 \times 100}{30} = 500 N$

Suggest Corrections

Similar questions

A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of radius 30 m. What horizontal force on the scooter is needed to make the turn possible ?

Q. A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of radius 30 m. What horizontal force on the scooter is needed to make the turn possible?

Q. A scooter weighing

150

kg together with its rider moving at

36 k m / h r

is to take a turn of radius

30

m. What force on the scooter towards the center is needed to make the turn possible? Who or what provides this?

A scooter weighing

150 k g

together with its rider moving at

36 k m / h r

is to take a turn of radius

30 m

If the horizontal force needed for the turn in the previous problem is to be supplied by the normal force by the road, what should be the proper angle of banking?

Q. A motorcycle rider covers 160 km in 2hrs A scooter rider covers 270 km in 3hrs What is the ratio of the speed of scooter rider to that of motorcycle rider??

Join BYJU'S Learning Program

A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of a radius 30 m. What horizontal force on the scooter is needed to make the turn possible?

Given: Mass = m = 150 kg Speed = v = 36 km/hr = 10 m/s Radius of turn = r = 30 m Let the horizontal force needed to make the turn be F. We have: F=mv2r=150×(10)230=150×10030=500 N

Given:
Mass = m = 150 kg
Speed = v = 36 km/hr = 10 m/s
Radius of turn = r = 30 m
Let the horizontal force needed to make the turn be F. We have:
$F = \frac{m v^{2}}{r} = \frac{150 \times (10)^{2}}{30} = \frac{150 \times 100}{30} = 500 N$