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Finding CGST and SGST

A shopkeeper ...

Question

A shopkeeper has a rope piece of length $120 c m$ and another of length $150 c m .$ He cuts the ropes into pieces of equal length as long as possible. What was the length of each piece he cut?

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Solution

Solution:
rope piece length $120 = 2 \times 3 \times 3 \times 10$
rope piece length $150 = 5 \times 3 \times 10$
The highest common factor is $30$

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