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Question

A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 1012/sec. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver =108 and Avagadro number =6.02×1023 gm mol1).

A
2.2N/m
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B
5.5N/m
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C
6.4N.m
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D
7.1N/m
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Solution

The correct option is D 7.1N/m
Time period of SHM is given by:
T=2πmk
Frequency=12πkm=1012
where m = mass of one atom
=1086.02×1023×103kg
12πk108103×6.02×1023
so k=7.1Nm

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