A simple pendulum of length $1m$ has a bob of mas$10g$. Find the work done in moving the pendulum from a vertical position to a horizontal position. Take $g=10m{s}^{-2}$.

Q. A simple pendulum bob takes 0.5 seconds to move from mean position to an extreme end, then find the length of the simple pendulum approximately in m (take g $=$ 9.8 m s${}^{-2}$)

Q. A simple pendulum 1 metre long has a bob of 10 kg. lf the pendulum swings from a horizontal position, the kinetic energy of the bob, at the instant it passes through the lowest position of its path is: (Take $g=9.8/m/s^2$)

Q.

A simple pendulum 1m long has a Bob of 10kg. If the pendulum swings from a horizontal position, the KE of the Bob at the instant it passes through the lowest position of it's path is

Q. A pendulum bob has a speed of $3$ ${ms}^{-1}$ at its lowest position. The pendulum is$0.5$ $m$ long. The speed of the bob, when the length makes an angle of ${60}^{\circ }$ to the vertical will be $(g=10$ $\left(n{s}^{-1}\right)$

Q. The bob of a simple pendulum is given a velocity in horizontal direction when the bob is at lowest position ,so that the bob describes vertical circle of radius equal to length of pendulum and tension in the string is $10N$ when the bob is at an angle ${60}^0$ from lowest position of vertical circle. The tension in the string when the bob reaches highest position is (The mass of bob is $100$ gram. $g=10m{s}^{–2}$):