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Question
A small laser emits light at power 5 mW and wavelength 633 nm. The laser beam is focused (narrowed) until its diameter matches the 1266 nm diameter of a sphere placed in its path. The sphere is perfectly absorbing and has density 5×103 kg/m3. What is the magnitude of the acceleration that force alone would give the sphere ?
A small laser emits light at power 5 mW and wavelength 633 nm. The laser beam is focused (narrowed) until its diameter matches the 1266 nm diameter of a sphere placed in its path. The sphere is perfectly absorbing and has density 5×103 kg/m3. What is the magnitude of the acceleration that force alone would give the sphere ?
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Solution
The correct option is C 3144 m/s2
Given:
λ=633 nm; d=1266 nm
ρ=5×103 kg/m3
Power=5×10−3 W
Since, sphere is perfectly absorbing, so force exerted on the sphere will be
F=IAc=Powerc=5×10−33×108
F=1.67×10−11 N
Mass of sphere,
m=ρ×πd36=5×103×π6×(1266×10−9)3
m=5.312×10−15 kg
Therefore, acceleration of the sphere due to incident rays will be,
a=Fm=1.67×10−115.312×10−15=3144 m/s2
Hence, option (D) is correct.
Given:
λ=633 nm; d=1266 nm
ρ=5×103 kg/m3
Power=5×10−3 W
Since, sphere is perfectly absorbing, so force exerted on the sphere will be
F=IAc=Powerc=5×10−33×108
F=1.67×10−11 N
Mass of sphere,
m=ρ×πd36=5×103×π6×(1266×10−9)3
m=5.312×10−15 kg
Therefore, acceleration of the sphere due to incident rays will be,
a=Fm=1.67×10−115.312×10−15=3144 m/s2
Hence, option (D) is correct.
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