A small pin fixed on a tabletop is viewed from above from a distance of $50\text{cm}$. By what distance would the pin appear to be raised if it is viewed from the same point through a $15\text{cm}$ thick glass slab held parallel to the table? Refractive index of glass = 1.5. Does the answer depend on the location of the slab?

Step 1: Find the value of apparent depth.

Given,
Actual depth of the pin, $d=15\text{cm}$.
Refractive index of glass, $\mu =1.5$.
Let the apparent depth of the pin be $d^{\prime }$.
Ratio of actual depth to the apparent depth is equal to the refractive index of glass, i.e.
$\mu =\frac{d}{d^{\prime }}=1.5=\frac{15}{d^{\prime }}$
$d^{\prime }=\frac{15}{1.5}$
$d^{\prime }=10\text{cm}$

The distance by which the pin appears to be raised $=15-10=5\text{cm}$

For a small angle of incidence, this distance does not depend upon the location of the slab.

Final Answer: Raised by $5\text{cm}$, No.