A solid rectangular piece of iron measures 1-05 in - 70 cm - 1-5 cm- Find the weight of this piece in kilograms if 1 cm-3 of iron weighs 8 grams-

Length of iron (l)=1.05 m =105 cm breadth (b)=70 cm and height (h)=1.5 cm ∴ volume of iron =l × b × h =105 × 70 × 1.5 cm^3 =11025 cm^3 weight of 1 cm^3 iron =8 ...

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Standard VIII

Mathematics

Volume of a Cuboid

A solid recta...

Question

A solid rectangular piece of iron measures $1.05 i n \times 70 c m \times 1.5 c m$ . Find the weight of this piece in kilograms if $1 c m^{3}$ of iron weighs 8 grams.

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Solution

Length of iron (l)=1.05 m

=105 cm

breadth (b)=70 cm

and height (h)=1.5 cm

$∴$ volume of iron $= l \times b \times h = 105 \times 70 \times 1.5 c m^{3}$

$= 11025 c m^{3}$

weight of $1 c m^{3}$ iron =8 gram

$∴$ Total weight $= 11025 \times 8 = 88200 g$

$= \frac{88200}{1000} k g$

=88.2 kg

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A solid rectangular piece of iron measures 1.05in×70cm×1.5cm. Find the weight of this piece in kilograms if 1cm3 of iron weighs 8 grams.

Length of iron (l)=1.05 m =105 cm breadth (b)=70 cm and height (h)=1.5 cm ∴ volume of iron =l×b×h=105×70×1.5cm3 =11025cm3 weight of 1cm3 iron =8 gram ∴ Total weight =11025×8=88200g =882001000kg =88.2 kg

A solid rectangular piece of iron measures $1.05 i n \times 70 c m \times 1.5 c m$ . Find the weight of this piece in kilograms if $1 c m^{3}$ of iron weighs 8 grams.

Length of iron (l)=1.05 m

=105 cm

breadth (b)=70 cm

and height (h)=1.5 cm

$∴$ volume of iron $= l \times b \times h = 105 \times 70 \times 1.5 c m^{3}$

$= 11025 c m^{3}$

weight of $1 c m^{3}$ iron =8 gram

$∴$ Total weight $= 11025 \times 8 = 88200 g$

$= \frac{88200}{1000} k g$

=88.2 kg