A solution of $1.25$ g of a certain non-volatile substance in $20$ g of water freezes at $271.94$ K. Calculate the molecular mass of the solute $(K_f=1.86K.kg.mo{l}^{-1})$.

Q. A solution of 1.25 g of a non - electrolyte in 20 g of water freezes at 271.94 K. If $K_f$ = 1.86 K molality -1 then the molecular wt. of the solute is

Q.

A solution of 1.25g of non - electrolyte in 20g of water freezes at 271.94 K. If K_f = 1.86 K kg mol^-1,then the molecular weight of the solute will be:

Q. A current of dry air was passed through a solution of $2.5$ g of a non-volatile solute in $100$ g of water and through water alone. The loss in the weight of solution was $1.25$ g and that of water was $0.005$ g. Calculate the molecular mass of the solute.

Q. $40$ g of a substance were dissolved in $450$ g of water to give a solution which freezes at $-{0.8}^{\circ }C$. Calculate molecular weight of substance. $K_f$ for water = $1.86$ K kg mol-1.

Q. On dissolving 0.25 g of a non-volatile substance in 30 mL benzene (density 0.8 g / mL), its freezing point decreases by ${0.40}^{o}C$. Calculate the molecular mass of non-volatile substance ($K_f=5.12Kkgmo{l}^{-1}$).