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Question

A spy report about a suspected car reads as follows. "The car moved 2.00 km towards east, made a perpendicular left turn, ran for 500 m, made a perpendicular right turn, ran for 4.00 km and stopped". Find the displacement of the car.

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Solution

AD=2ˆi+0.5ˆj+4ˆi

= 6ˆi+0.5ˆj

AD=AE2+DE2


=62+(0.5)2

=6.02 km

Now, tan θ=DEAE=.56

θ=tan1(112)

Hence displacement of the car is 6.02 km along the direction tan1(112) with +ve
x-axis.



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