A spy report about a suspected car reads as follows. "The car moved 2.00 km towards east, made a perpendicular left turn, ran for 500 m, made a perpendicular right turn, ran for 4.00 km and stopped". Find the displacement of the car.
→AD=2ˆi+0.5ˆj+4ˆi
= 6ˆi+0.5ˆj
AD=√AE2+DE2
=√62+(0.5)2
=6.02 km
Now, tan θ=DEAE=.56
⇒θ=tan−1(112)
Hence displacement of the car is 6.02 km along the direction tan−1(112) with +ve
x-axis.